How far do you fall in 3 seconds?
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Ava Martinez
Studied at Stanford University, Lives in Palo Alto, CA
As a physicist, I can tell you that the distance you fall in a vacuum, assuming no air resistance, can be calculated using the equations of motion for an object in free fall. The formula to calculate the distance \( d \) fallen in time \( t \) is given by:
\[ d = \frac{1}{2} g t^2 \]
where \( g \) is the acceleration due to gravity, which is approximately \( 9.81 \, \text{m/s}^2 \) on the surface of the Earth.
For a fall of 3 seconds, the distance \( d \) would be:
\[ d = \frac{1}{2} \times 9.81 \, \text{m/s}^2 \times (3 \, \text{s})^2 \]
\[ d = \frac{1}{2} \times 9.81 \times 9 \, \text{m} \]
\[ d = 4.905 \times 9 \, \text{m} \]
\[ d = 44.145 \, \text{m} \]
So, you would fall approximately 44.145 meters in 3 seconds.
\[ d = \frac{1}{2} g t^2 \]
where \( g \) is the acceleration due to gravity, which is approximately \( 9.81 \, \text{m/s}^2 \) on the surface of the Earth.
For a fall of 3 seconds, the distance \( d \) would be:
\[ d = \frac{1}{2} \times 9.81 \, \text{m/s}^2 \times (3 \, \text{s})^2 \]
\[ d = \frac{1}{2} \times 9.81 \times 9 \, \text{m} \]
\[ d = 4.905 \times 9 \, \text{m} \]
\[ d = 44.145 \, \text{m} \]
So, you would fall approximately 44.145 meters in 3 seconds.
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Studied at Stanford University, Lives in Palo Alto. Currently working as a software engineer at a leading tech company.
The first equation shows that, after one second, an object will have fallen a distance of 1/2 �� 9.8 �� 12 = 4.9 meters. After two seconds it will have fallen 1/2 �� 9.8 �� 22 = 19.6 meters; and so on.
2023-04-11 14:03:15
Alexander Wilson
QuesHub.com delivers expert answers and knowledge to you.
The first equation shows that, after one second, an object will have fallen a distance of 1/2 �� 9.8 �� 12 = 4.9 meters. After two seconds it will have fallen 1/2 �� 9.8 �� 22 = 19.6 meters; and so on.
